Explain the relationship between a region of the electromagnetic spectrum and the types of molecular or electronic transitions associated with that region.
Different regions of the electromagnetic spectrum carry different photon energies, and each energy range drives a different kind of transition. The CED lists exactly three:
The ordering follows the energy ordering: rotational energy gaps are smallest, vibrational gaps are larger, and electronic gaps are larger still. Match the gap to the photon energy and you know which region is required.
Absorption and color. A solution appears the complementary color of the visible light it absorbs. A solution that absorbs orange-red light looks blue. This matters when choosing the wavelength for a Beer–Lambert experiment (3.13): you set the instrument to the wavelength of maximum absorbance, which is not the color you see.
Emission spectra. When an excited electron falls back to a lower level, it emits a photon whose energy equals the gap between levels. Because atomic energy levels are quantized and unique to each element, the resulting line spectrum is an elemental fingerprint. Absorption spectra are the negative image: dark lines exactly where the emission lines would be.
A student wants to (a) identify whether a sample contains a C=O group, and (b) measure the concentration of a blue Cu²⁺ solution. Which region of the spectrum is appropriate for each, and why?
(a) Infrared. Identifying a functional group means detecting a characteristic bond vibration. The C=O stretch absorbs strongly near 1700 cm⁻¹ in the infrared, because IR photon energies match vibrational energy gaps. UV/vis would give no functional-group information.
(b) Visible. Measuring the concentration of a colored ion relies on an electronic transition, which falls in the UV/visible region. The Cu²⁺ solution looks blue, meaning it transmits blue and absorbs the complementary orange-red light around 600–650 nm. The student should set the spectrophotometer near that absorbance maximum (λ_max) to get the greatest sensitivity, then apply the Beer–Lambert law.