Explain the relationship between the photoelectron spectrum of an atom or ion and (i) the ground-state electron configuration of the species, and (ii) the interactions between the electrons and the nucleus.
Photoelectron spectroscopy (PES) is the experiment that makes electron configuration visible. High-energy photons strike a sample and eject electrons; the instrument measures the kinetic energy of each ejected electron and works backward to its binding energy — the energy that was holding it to the atom.
EK 1.6.A.1 gives you exactly two rules for reading the spectrum:
So a spectrum with peaks in the height ratio 2 : 2 : 4 must be 1s² 2s² 2p⁴ — eight electrons, oxygen. The configuration falls out of the picture.
Position is governed by effective nuclear charge. Core electrons sit close to the nucleus, are barely shielded, and have enormous binding energies. Valence electrons are farther out and shielded by every inner shell, so they come off far more easily. Within a single shell, s electrons penetrate closer to the nucleus than p electrons, so 2s binds slightly more tightly than 2p.
Comparing two elements' spectra is a direct probe of Zeff: the 1s peak of nitrogen sits at higher binding energy than the 1s peak of carbon because nitrogen has one more proton pulling on essentially the same core.
A PES spectrum shows peaks at 104, 6.84, and 3.67 MJ/mol with relative heights 2, 2, and 1. Identify the element and justify your answer.
Electron count: 2 + 2 + 1 = 5 electrons → boron (Z = 5).
Assignment:
104 MJ/mol (height 2) → 1s², the core electrons, held most tightly.
6.84 MJ/mol (height 2) → 2s².
3.67 MJ/mol (height 1) → 2p¹.
Justification: the 1s electrons experience nearly the full +5 nuclear charge with essentially no shielding, so their binding energy is more than an order of magnitude larger. The 2s electron penetrates closer to the nucleus than the 2p electron and is therefore less shielded, which is why 2s binds more tightly than 2p even though both are in the n = 2 shell.