Identify the qualitative effect of changes in pH on the solubility of a salt.
The solubility of a salt is pH sensitive when one of its constituent ions is a weak acid, a weak base, or the hydroxide ion. These effects can be understood qualitatively using Le Châtelier's principle.
The mechanism. Consider a salt whose anion is a weak base:
CaF₂(s) ⇌ Ca²⁺(aq) + 2 F⁻(aq)
F⁻(aq) + H₃O⁺(aq) ⇌ HF(aq) + H₂O(l)
Adding acid consumes F⁻ by converting it to HF. That removes a product from the first equilibrium, which shifts right, so more CaF₂ dissolves. In Q terms: consuming F⁻ drops Qsp below Ksp, and the system responds by dissolving more solid.
Which salts are pH sensitive? Those whose anion is the conjugate base of a weak acid, so it can actually grab a proton:
Hydroxide salts are the most dramatic case. Mg(OH)₂ dissolves readily in acid because H₃O⁺ consumes OH⁻ directly. Conversely, raising the pH adds OH⁻, which is a common ion, and suppresses the solubility of any metal hydroxide.
Carbonates are the everyday example: CaCO₃ in limestone, marble, and seashells dissolves in acid because CO₃²⁻ is protonated to HCO₃⁻ and then to H₂CO₃, which decomposes to CO₂ gas. Acid rain damage to marble monuments is exactly this reaction.
Predict and explain the effect of lowering the pH on the solubility of (a) CaCO₃, (b) AgCl, and (c) Mg(OH)₂.
(a) CaCO₃ — solubility increases substantially.
CaCO₃(s) ⇌ Ca²⁺(aq) + CO₃²⁻(aq)
Carbonate is the conjugate base of the weak acid HCO₃⁻, so added H₃O⁺ protonates it:
CO₃²⁻ + H₃O⁺ → HCO₃⁻ + H₂O, and further HCO₃⁻ + H₃O⁺ → H₂CO₃ → CO₂(g) + H₂O
Removing carbonate from solution drives the dissolution equilibrium to the right, so more CaCO₃ dissolves. The escaping CO₂ gas removes product permanently, pushing the reaction essentially to completion — this is why limestone visibly fizzes in acid.
(b) AgCl — essentially no effect.
AgCl(s) ⇌ Ag⁺(aq) + Cl⁻(aq)
Chloride is the conjugate base of HCl, a strong acid, which means Cl⁻ is an extremely weak base and is not measurably protonated at any accessible pH. Since neither ion is removed from solution, the dissolution equilibrium is undisturbed and solubility is unchanged.
(c) Mg(OH)₂ — solubility increases greatly.
Mg(OH)₂(s) ⇌ Mg²⁺(aq) + 2 OH⁻(aq)
Added H₃O⁺ neutralizes hydroxide directly: H₃O⁺ + OH⁻ → 2 H₂O. Removing OH⁻ shifts the dissolution equilibrium sharply to the right. This is why milk of magnesia, a suspension of Mg(OH)₂, dissolves in stomach acid and neutralizes it.