Represent the activation energy and overall energy change in a multistep reaction with a reaction energy profile.
Knowing the energetics of each elementary reaction in a mechanism allows construction of an energy profile for the whole multistep reaction. The profile is simply the single-step profiles chained together.
How to read it:
A subtlety worth getting right: the rate-determining step is not always the step with the tallest individual barrier drawn on the page. It is the step whose transition state is highest in absolute energy relative to the preceding stable species — because that is the largest energy hill the system must climb from where it is sitting.
Individual step enthalpies can be read the same way as ΔH for the whole reaction: the level of the intermediate minus the level of the reactants gives ΔH for step 1, and so on. They sum to the overall ΔH — Hess's law visible on a graph (see 6.9).
A two-step mechanism has these energies (kJ/mol relative to reactants at 0): TS1 at +95, intermediate at +30, TS2 at +75, products at −50. Identify the rate-determining step, give Ea for each step, and give the overall ΔH.
Step 1: reactants (0) → TS1 (+95) → intermediate (+30)
Ea(step 1) = 95 − 0 = 95 kJ/mol
ΔH(step 1) = 30 − 0 = +30 kJ/mol (endothermic)
Step 2: intermediate (+30) → TS2 (+75) → products (−50)
Ea(step 2) = 75 − 30 = 45 kJ/mol
ΔH(step 2) = −50 − 30 = −80 kJ/mol (exothermic)
Rate-determining step: step 1. Its activation energy (95) is larger than step 2's (45), and its transition state is the highest point on the entire profile, so it is the bottleneck.
Overall ΔH = products − reactants = −50 − 0 = −50 kJ/mol (exothermic).
Check with Hess's law: +30 + (−80) = −50 ✓