Represent a chemical or physical process as a sequence of steps; explain the relationship between the enthalpy of a process and the sum of the enthalpies of the individual steps.
Many processes can be broken down into a series of steps, each with its own energy change.
EK 6.9.B.1 gives the justification, and it is worth reading closely because it is a first-law argument: because total energy is conserved, and each individual reaction in a sequence transfers thermal energy to or from the surroundings, the net thermal energy transferred in the sequence equals the sum of the transfers in each step. Those transfers result from potential-energy changes among the species, so at constant pressure the enthalpy change of the overall process equals the sum of the enthalpy changes of the individual steps.
EK 6.9.B.2 lists the two manipulation rules:
The strategy for solving a Hess's law problem:
Practical anchor: start with a species that appears in only one of the given equations. That fixes the required operation on that equation with no ambiguity, and the rest follows.
The same logic reappears for equilibrium constants (7.6) — except that combining equilibria multiplies K rather than adding it.
Calculate ΔH for 2 C(graphite) + H₂(g) → C₂H₂(g) given: (1) C₂H₂(g) + 5/2 O₂(g) → 2 CO₂(g) + H₂O(l) ΔH = −1299.6 kJ (2) C(graphite) + O₂(g) → CO₂(g) ΔH = −393.5 kJ (3) H₂(g) + ½ O₂(g) → H₂O(l) ΔH = −285.8 kJ
Target: 2 C(graphite) + H₂(g) → C₂H₂(g)
Place C₂H₂: it must be a product, but in equation (1) it is a reactant. Reverse (1):
2 CO₂(g) + H₂O(l) → C₂H₂(g) + 5/2 O₂(g) ΔH = +1299.6 kJ
Place C(graphite): needed as a reactant with coefficient 2. Equation (2) has it as a reactant with coefficient 1. Multiply (2) by 2:
2 C(graphite) + 2 O₂(g) → 2 CO₂(g) ΔH = 2(−393.5) = −787.0 kJ
Place H₂: needed as a reactant with coefficient 1. Equation (3) already has it that way. Use as is:
H₂(g) + ½ O₂(g) → H₂O(l) ΔH = −285.8 kJ
Add and cancel: 2 CO₂ cancels; H₂O(l) cancels; oxygen: 2 + ½ = 5/2 on the left cancels 5/2 on the right ✓
Result: 2 C(graphite) + H₂(g) → C₂H₂(g) ✓
ΔH = 1299.6 − 787.0 − 285.8 = +226.8 kJ
Positive, meaning acetylene is less stable than its constituent elements — consistent with its high reactivity.