Represent the relationship between potential energy and distance between atoms, based on factors that influence the interaction strength.
A graph of potential energy versus internuclear distance is the CED's preferred model for a chemical bond. Read two quantities off it:
The shape has a physical story. At very large r there is essentially no interaction and PE is flat at zero. As the atoms approach, attraction between each nucleus and the other's electrons lowers the energy. Push them too close and nucleus–nucleus (and core electron) repulsion sends PE steeply upward. The minimum is the balance point.
Two factors control where that minimum sits and how deep it is:
For ionic interactions, EK 2.2.A.3 says to reason with Coulomb's law directly:
Rank NaF, MgO, and KBr by expected melting point, highest first. Justify with Coulomb’s law.
MgO > NaF > KBr
MgO has Mg²⁺ and O²⁻. The product of the charges is (2)(2) = 4, four times larger than for any 1+/1− pair, so the Coulombic attraction is far stronger and much more energy is needed to separate the ions.
NaF vs KBr — both are 1+/1−, so charge cannot distinguish them. Na⁺ is smaller than K⁺ and F⁻ is smaller than Br⁻, so the internuclear distance r in NaF is smaller. Since force is proportional to 1/r², NaF has the stronger attraction and the higher melting point.